(y^2+2x^2y)dx+(2x^3-xy)dy=0

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Solution for (y^2+2x^2y)dx+(2x^3-xy)dy=0 equation:


Simplifying
(y2 + 2x2y) * dx + (2x3 + -1xy) * dy = 0

Reorder the terms:
(2x2y + y2) * dx + (2x3 + -1xy) * dy = 0

Reorder the terms for easier multiplication:
dx(2x2y + y2) + (2x3 + -1xy) * dy = 0
(2x2y * dx + y2 * dx) + (2x3 + -1xy) * dy = 0

Reorder the terms:
(dxy2 + 2dx3y) + (2x3 + -1xy) * dy = 0
(dxy2 + 2dx3y) + (2x3 + -1xy) * dy = 0

Reorder the terms:
dxy2 + 2dx3y + (-1xy + 2x3) * dy = 0

Reorder the terms for easier multiplication:
dxy2 + 2dx3y + dy(-1xy + 2x3) = 0
dxy2 + 2dx3y + (-1xy * dy + 2x3 * dy) = 0
dxy2 + 2dx3y + (-1dxy2 + 2dx3y) = 0

Reorder the terms:
dxy2 + -1dxy2 + 2dx3y + 2dx3y = 0

Combine like terms: dxy2 + -1dxy2 = 0
0 + 2dx3y + 2dx3y = 0
2dx3y + 2dx3y = 0

Combine like terms: 2dx3y + 2dx3y = 4dx3y
4dx3y = 0

Solving
4dx3y = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Divide each side by '4'.
dx3y = 0

Simplifying
dx3y = 0

The solution to this equation could not be determined.

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